In Farmer Stone's hay loft, there were several animals, in particular birds, mice, and cockroaches. One day, feeling bored, I decided to count the animals.
I found there were exactly 150 feet and 50 heads in total, and there were twice as many cockroaches as mice.
Hint
Cockroaches have 6 feet, mice have 4, and birds have 2. They all have one head!
Answer
35 birds, 5 mice, and 10 cockroaches.
Reasoning
Cockroaches have 6 feet, mice have 4, and birds have 2. They each have one head.
We can write down expressions for the heads and the feet, calling birds B, mice M, and cockroaches C.
Counting the heads: (1) B + M + C = 50
Counting the feet: (2) 2B + 4M + 6C = 150
We are told that for every mouse there are two cockroaches so, C = 2M. Update (1) and (2) to give: (3) B + 3M = 50 (4) 2B + 16M = 150
If we double (3) we get: (5) 2B + 6M = 100
We can now do (4) − (5) to give: 10M = 50 M = 5
So, we have 5 mice (and 10 cockroaches).
We can use M = 5 in (3) to give: B + 3 x 5 = 50 B + 15 = 50 B = 35
So, C = 10, M = 5 and B = 35.
Double-Checking
10 cockroaches have 10 heads and 60 feet.
5 mice have 5 heads and 20 feet.
35 birds have 35 heads and 70 feet.
The total number of heads = 10 + 5 + 35 = 50.
The total number of feet = 60 + 20 + 70 = 150.
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Puzzle 2
The Winter Festival is well underway and BrainBashers control is working out the plane times for the return journeys.
Unfortunately, the BrainBashers timetable software is playing up again and has worked out the times incorrectly, as shown below.
France 4.00pm
Mexico 3.00pm
Jamaica 5.00pm
Japan 1.00pm
According to the software, at what time is the return trip to Finland?
Reasoning There are 61 squares of size 1 x 1. There are 37 squares of size 2 x 2. There are 15 squares of size 3 x 3. There are 3 squares of size 4 x 4.
