Alex is a keen dog admirer and over the years has had a number of dogs.
Alex has had an Alsatian, a Dalmatian, a Poodle, and a Great Dane, but not necessarily in that order.
Alex had Jamie first.The Dalmatian was an adored pet before the Great Dane.Sammy, the Alsatian, was the second dog Alex loved.Whitney was owned before the Poodle.Jimmy was not a Great Dane.
Can you match the dogs to their names and find the order in which Alex had them?
Answer # Name Breed
1 Jamie Dalmatian
2 Sammy Alsatian
3 Whitney Great Dane
4 Jimmy Poodle
Reasoning
(Clue 1) Jamie was first, and (Clue 3) Sammy the Alsatian was second: # Name Breed
1 Jamie
2 Sammy Alsatian
3
4
(Clue 4) Whitney was owned before the poodle, leaving Jimmy last: # Name Breed
1 Jamie
2 Sammy Alsatian
3 Whitney
4 Jimmy Poodle
(Clue 2) the Dalmatian was before the Great Dane: # Name Breed
1 Jamie Dalmatian
2 Sammy Alsatian
3 Whitney Great Dane
4 Jimmy Poodle
??
Puzzle 6
Below, 10 nine-letter words have been broken into chunks of three letters.
The chunks have been moved around, no chunk is used twice, and all of the chunks are used.
Can you determine what the 10 words are?
ely rec ant htn fer ort
ent cer por sin lig ian
lio row use rar lib ive
tfo sca ing ing far eth
som dif est dig imp mho
Hint
The first letters of the words are: D, D, F, I, L, L, P, S, S, S.
Answers
dif + fer + ent = different
dig + est + ive = digestive
far + mho + use = farmhouse
imp + ort + ant = important
lib + rar + ian = librarian
lig + htn + ing = lightning
por + tfo + lio = portfolio
sca + rec + row = scarecrow
sin + cer + ely = sincerely
som + eth + ing = something
Answer
If the sum of the digits is divisible by nine, so is the number.
Add up all of the digits in the number and see if the sum is divisible by 9. If you still can't tell, you can add those digits again to see if the new sum is divisible by 9. You can keep going until you the sum is obviously divisible by 9 or not.
For example, is 486451464 divisible by 9?
Do 4 + 8 + 6 + 4 + 5 + 1 + 4 + 6 + 4 = 42.
Is 42 divisible by 9? Not sure, you can then do:
4 + 2 = 6. Which clearly isn't divisible by 9. So our original number, 486451464, isn't either.
?
Puzzle 8
Last week I drove from Aardvark to Beeville.
On the first day, I travelled 1/3 of the starting distance.
On day two, I travelled 1/2 of the remaining distance.
On day three, I travelled 2/3 of the remaining distance.
At the end of day four, after travelling 3/4 of the remaining distance, I was still 5 miles away from Beeville.
The total distance was 180 miles, but as I still had 5 miles to go, the required answer is 175 miles.
Reasoning
Let's try working backwards.
Day 4: I travelled 3/4, which means that the other 1/4 was 5 miles, and 20 miles were left at the start of day four.
Day 3: I travelled 2/3, which means that the other 1/3 was 20 mile, and 60 miles were left at the start of day three.
Day 2: I travelled 1/2, which means that the other 1/2 was 60 miles, and 120 miles were left at the start of day two.
Day 1: I travelled 1/3, which means that the other 2/3 was 120 miles, and 180 miles were ahead at the start of day one.
The full distance was therefore 180 miles, but we were asked how many miles I had travelled so far, and as I still had 5 to go the answer is 175 miles.
Double-Checking
Start distance: 180 miles.
Day 1: I travelled 1/3 of the distance (60 miles), leaving 120 miles.
Day 2: I travelled 1/2 of the distance (60 miles), leaving 60 miles.
Day 3: I travelled 2/3 of the distance (40 miles), leaving 20 miles.
Day 4: I travelled 3/4 of the distance (15 miles), leaving 5 miles.
