Reasoning
Q1 can't have A as its answer (otherwise it would contradict itself).
If Q1's answer was C (meaning Q4's answer was A), then Q3's answer would be C. However, Q2's answer should now be A, but this isn't allowed by Q1 (as Q4 is the first answer with A). This is a contradiction.
Therefore, Q1's answer is B (meaning Q3's answer is A).
For Q2's answer to be C, Q4's answer would have to be A, which would contradict Q4. Therefore, Q2's answer is B making Q4's answer B.
During the latest round of the BrainBashers school triathlon the final results were mislaid, however, this is what we do know.
Hayden was fourth. Alex was not the oldest but was older than Drew, who was not second. The child who was next in age to the youngest, finished second. The child who finished in third place was older than the child who finished first. Billie was younger than the child who finished in third place.
Can you determine who finished where and place the children in order of age?
Answer # Name Age
#1 Drew youngest
#2 Billie next to youngest
#3 Alex next to oldest
#4 Hayden oldest
Reasoning
By (2), neither Alex nor Drew were the oldest. By (5), neither was Billie. Therefore, Hayden was the oldest, and by (1) came fourth.
#1
#2
#3
#4 Hayden oldest
By (4) the youngest didn't come third, and by (3) the youngest didn't come second. Therefore, the youngest came first.
#1 youngest
#2
#3
#4 Hayden oldest
By (3), the next to youngest came second, leaving the next to oldest in third.
#1 youngest
#2 next to youngest
#3 next to oldest
#4 Hayden oldest
By (2), Drew wasn't second, but Alex was older, so Drew can't be third either. Therefore, Drew can only have come in first.
#1 Drew youngest
#2 next to youngest
#3 next to oldest
#4 Hayden oldest
By (5) Billie didn't come third, so came second. Leaving Alex in third.
#1 Drew youngest
#2 Billie next to youngest
#3 Alex next to oldest
#4 Hayden oldest
Reasoning
These are geometric shapes, the number of sides increases, and the words are reversed.
3 elgnairt = triangle
4 erauqs = square
5 nogatnep = pentagon
6 nogaxeh = hexagon
7 nogatpeh = heptagon
8 nogatco = octagon
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