In my collection of classical music, I have a range of pieces that last 6, 7, 8 and 9 minutes.
The piece by Bach lasts 8 minutes, and the CD lasts longer than the piece by Holst. The piece on DAT tape is longer than the piece by Beethoven. The single lasts 7 minutes, and the album does not contain any Holst. The piece by Butler is on the DAT tape.
Can you determine which piece of music is in which format, and how long each lasts?
Answer Composer Format Length
Beethoven album 6
Holst single 7
Bach CD 8
Butler DAT 9
Reasoning
By (1), the piece by Bach lasts 8 minutes. By (3), the single lasts 7 minutes. Composer Format Length
6
single 7
Bach 8
9
By (4), the piece by Butler is on the DAT tape. But, by (2), this can't be the shortest, so it must be 9 minutes long. Composer Format Length
6
single 7
Bach 8
Butler DAT 9
By (1), the CD can't be the shortest, so must be 8 minutes long. Composer Format Length
6
single 7
Bach CD 8
Butler DAT 9
The album must therefore be 6 minutes long, and by (3) doesn't contain any Holst. Composer Format Length
album 6
Holst single 7
Bach CD 8
Butler DAT 9
Which means that the album was the piece by Beethoven. Composer Format Length
Beethoven album 6
Holst single 7
Bach CD 8
Butler DAT 9
??
Puzzle 6
Can you find a five-digit number that has no zeros nor ones in it and no digit is repeated, where:
The fourth digit is a quarter of the total of all of the digits.The second digit is twice the first digit.The third digit is the largest.The last digit is the sum of the first two digits.
Reasoning
We can start by labelling the digits as ABCDE.
We know that:
(i) B = 2 x A
and:
E = A + B
And using (i) we get:
E = A + (2 x A) (ii) E = 3 x A
If A = 1, this isn't allowed (as there are no 1's in the puzzle).
If A = 2, then B = 4, and E = 6.
If A = 3, then B = 6, and E = 9, but this isn't allowed (as C has to be the largest digit).
So, A = 2, B = 4, E = 6, and we now have to find C and D.
We also know that:
D = (A + B + C + D + E) ÷ 4
And using (i) and (ii) we get:
D = [A + (2 x A) + C + D + (3 x A)] ÷ 4
so:
3 x D = (6 x A) + C
so:
(iii) D = [(6 x A) + C] ÷ 3
C can only be 7, 8 or 9 (as it's the largest digit, and we've already found 6) and (iii) tells us that it must be a multiple of 3, which means that C = 9. Leaving D = 7.
So the final number is: 24976.
Double-Checking
The answer is 24976.
The fourth digit is a quarter of the total of all of the digits.
A + B + C + D + E = 2 + 4 + 9 + 7 + 6 = 28, and 28 ÷ 4 = 7.
The second digit is twice the first digit.
4 = 2 x 2.
The third digit is the largest.
9 is the largest digit.
The last digit is the sum of the first two digits.
6 = 2 + 4.
??
Puzzle 7
Below you will find 15 well-known five-letter words, with only their endings remaining.
Can you find the words? --pay--lad--ior--eue--rva--day--voc--yss--gun--pty--til--cay--uke--uze--noe
Reasoning
These are the initial letters of the planets.
M = Mercury
V = Venus
E = Earth
M = Mars
J = Jupiter
S = Saturn
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