Puzzle 97
Alex's Dogs - Logic Puzzles
Alex is a keen dog admirer and over the years has had a number of dogs.
Alex has had an Alsatian, a Dalmatian, a Poodle, and a Great Dane, but not necessarily in that order.
Alex had Jamie first. The Dalmatian was an adored pet before the Great Dane. Sammy, the Alsatian, was the second dog Alex loved. Whitney was housed before the Poodle and Jimmy was not a Great Dane.
Can you match the dogs to their names and find the order in which Alex had them?
Puzzle Copyright © Kevin Stone
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Hint
Which dog was first, and which was second?
Answer
# Name Breed
1 Jamie Dalmatian
2 Sammy Alsatian
3 Whitney Great Dane
4 Jimmy Poodle
Reasoning
Breaking down the clues, and numbering them:
Alex had Jamie first.
The Dalmatian was an adored pet before the Great Dane.
Sammy, the Alsatian, was the second dog Alex loved.
Whitney was housed before the Poodle.
Jimmy was not a Great Dane.
(Clue 1) Jamie was first, and (Clue 3) Sammy the Alsatian was second:
# Name Breed
1 Jamie
2 Sammy Alsatian
3
4
(Clue 4) Whitney was housed before the poodle, leaving Jimmy last:
# Name Breed
1 Jamie
2 Sammy Alsatian
3 Whitney
4 Jimmy Poodle
(Clue 2) the Dalmatian was before the Great Dane:
# Name Breed
1 Jamie Dalmatian
2 Sammy Alsatian
3 Whitney Great Dane
4 Jimmy Poodle
Puzzle 98
By changing the second letter of each word below, you can make another valid word.
Can you change each word such that the second letters will reveal an eleven-letter word when read downwards?
Therefore, what now reads AWPYRNUCEPA will be a real word.
BAKE
SWAP
OPAL
DYED
ARKS
SNOW
LUMP
ACES
MELT
SPUN
RANT
Puzzle Copyright © Kevin Stone
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Hint
The eleven-letter word begins with the letter I.
Answer
Investigate.
BAKE = BIKE
SWAP = SNAP
OPAL = OVAL
DYED = DEED
ARKS = ASKS
SNOW = STOW
LUMP = LIMP
ACES = AGES
MELT = MALT
SPUN = STUN
RANT = RENT
Puzzle 99
Triathlon - Round 2 - Logic Puzzles
The final of the BrainBashers triathlon was a close run thing.
The whole tournament was decided on the last two sections, cycling and the road race.
Alex didn't win either section.
The person who won the cycling came third in the road race.
Alex beat Charlie in cycling, but was beaten by Charlie in the road race.
Charlie was last in neither section.
Drew won the road race, but was beaten by Billie in the cycling.
Can you work out who came where in each section?
Puzzle Copyright © Kevin Stone
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Hint
Billie won the cycling.
Answer
Cycling : Billie > Alex > Charlie > Drew
Road race : Drew > Charlie > Billie > Alex
Puzzle 100
Farmer Stone is quite an eccentric dairy farmer.
He originally had a total of 54 gallons of milk in three churns, and he wanted to make sure each churn contained 18 gallons of milk.
In order to do this, he did the following:
First, he poured 1/4 of the first churn into the second churn.
He then poured 1/2 of the second churn into the third churn.
Finally, he poured 1/3 of the third churn into the first churn.
How many gallons did each churn contain before Farmer Stone started pouring?
Puzzle Copyright © Kevin Stone
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Hint
Try working backwards with each churn containing 18 gallons.
Answer
12, 33, and 9 gallons respectively for churns 1, 2, and 3.
Reasoning
Working backwards, at the end after Pour 3, the churns (C1, C2, C3) contained:
C1 C2 C3
————————————
18 18 18 after Pour 3
Pour3 was 1/3 of C3 into C1, the remaining 2/3 has to be the 18 gallons left in C3 after the pour, which means that 1/3 is 9 gallons. So 9 gallons was poured from C3 into C1. Before Pour3, C1 must have contained 9 gallons, and C3 contained 27 gallons.
C1 C2 C3
————————————
9 18 27 after Pour 2
18 18 18 after Pour 3
Pour2 was 1/2 of C2 into C3, the remaining 1/2 has to be the 18 gallons left in C2 after the pour, which means that 1/2 is 18 gallons. So 18 gallons was poured from C2 into C3. Before Pour2, C2 must have contained 36 gallons, and C3 contained 9 gallons.
C1 C2 C3
————————————
9 36 9 after Pour 1
9 18 27 after Pour 2
18 18 18 after Pour 3
Pour1 was 1/4 of C1 into C2, the remaining 3/4 has to be the 9 gallons left in C1 after the pour, which means that 1/4 is 3 gallons. So 3 gallons was poured from C1 into C2. Before Pour2, C1 must have contained 12 gallons, and C2 contained 33 gallons.
C1 C2 C3
————————————
12 33 9 at the start
9 36 9 after Pour 1
9 18 27 after Pour 2
18 18 18 after Pour 3
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