Puzzle 9
W B H F S K F V J P Z
H S S H T J P P N W L
A F P W P N T D S W S
T R H S P L M V R G B
I D P B D W S N R T C
S R S F T D B K K F B
O M F R L Z F R K Y P
N J Z J S Z N M B J Q
E R Z F Q Z V G Y F V
P P F G F W Z W N R P
L B J V R J H F K T Z
U H F K Y F W J F S R
S S W C Q R Q Y H R S
O M W F P R Q J K H R
N M B W S K B J Y D Q
E T J Y P F D L R P F
Puzzle Copyright © Kevin Stone
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Hint
The question is somewhere in the grid.
Answer
Two.
The first column reads 'WHAT IS ONE PLUS ONE'.
Puzzle 10
Using all of the letters A to Z, each once only, complete these common words:
-ai-e
s-ua-
-e-el
-o-ed
-na-e
fog--
c--mp
b--jo
-r-it
-re-t
-av-n
mu--c
mou--
Puzzle Copyright © Kevin Stone
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Hint
The first word begins with the letter M.
Answers
-ai-e = maize (MZ)
s-ua- = squad (QD)
-e-el = jewel (JW)
-o-ed = foxed (FX)
-na-e = knave (KV)
fog-- = foggy (GY)
c--mp = clump (LU)
b--jo = banjo (AN)
-r-it = orbit (OB)
-re-t = crept (CP)
-av-n = raven (RE)
mu--c = music (SI)
mou-- = mouth (TH)
The solution above uses common words, the solution below uses the less common word CLOMP.
-ai-e = maize (MZ)
s-ua- = squad (QD)
-e-el = jewel (JW)
-o-ed = boxed (BX)
-na-e = knave (KV)
fog-- = foggy (GY)
c--mp = clomp (LO)
b--jo = banjo (AN)
-r-it = fruit (FU)
-re-t = crept (CP)
-av-n = raven (RE)
mu--c = music (SI)
mou-- = mouth (TH)
Puzzle 11
At the local sweet shop, three particularly nice sweets are on special offer.
A Nobbler is over three times the price of a Sparkle.
Six Sparkles are worth more than a Wibbler.
A Nobbler, plus two Sparkles costs less than a Wibbler.
A Sparkle, a Wibbler and a Nobbler together cost 40p.
Can you determine the price of each type of sweet?
Puzzle Copyright © Kevin Stone
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Hint
Which sweet is the least expensive?
Answer
Sparkle = 4p
Wibbler = 23p
Nobbler = 13p
Reasoning
By (3) a Nobbler, plus two Sparkles costs less than a Wibbler, therefore a Wibbler must be the most expensive sweet.
By (1) a Nobbler is over three times the price of a Sparkle, therefore a Sparkle must be the cheapest sweet.
So the order of sweets, from the least to most expensive, is Sparkle, Nobbler, Wibbler.
If a Sparkle was 1p, by (2) a Wibbler could only be up to 5p, by (4) a Nobbler would cost at least 34p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 2p, by (2) a Wibbler could only be up to 11p, by (4) a Nobbler would cost at least 27p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 3p, by (2) a Wibbler could only be up to 17p, by (4) a Nobbler would cost at least 20p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
So a Sparkle must be at least 4p.
If a Sparkle was 4p, by (1) a Nobbler must be at least 13p, by (4) a Wibbler would cost 23p – this combination matches all of the clues and is a possible solution.
If a Sparkle was 4p and a Nobbler 14p, by (4) a Wibbler would cost 22p. This would not satisfy (3). And if we increase the price of a Nobbler, (3) is never satisfied.
If a Sparkle was 5p, by (1) a Nobbler must be at least 16p, by (4) making a Wibbler at most 19p. This would not satisfy (3).
If we increase the price of a Sparkle or Nobbler further, (3) is will never be satisfied.
Therefore, the only solution we came across must be the correct one.
Puzzle 12
Using all of the letters A to Z, each once only, complete these common words:
-e-rd
-u-et
wa-t-
-um-y
-e-er
a-o-e
mi--d
-hew-
hu-i-
-abi-
co--h
ho--e
arg--
Puzzle Copyright © Kevin Stone
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Hint
The first word begins with the letter B.
Answers
-e-rd = beard (BA)
-u-et = quiet (QI)
wa-t- = waltz (LZ)
-um-y = jumpy (JP)
-e-er = fever (FV)
a-o-e = awoke (WK)
mi--d = mixed (XE)
-hew- = chewy (CY)
hu-i- = humid (MD)
-abi- = habit (HT)
co--h = cough (UG)
ho--e = horse (RS)
arg-- = argon (ON)
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