Puzzle 149
Entry Exam Section D - Logic Puzzles
Here is a snippet of section D of the curious multiple-choice entrance exam into the exclusive BrainBashers puzzle club.
Q1. Which is the first question where c) is the correct answer?
a) Q3
b) Q4
c) Q1
d) Q2
Q2. Which is the first question where a) is the correct answer?
a) Q4
b) Q2
c) Q3
d) Q1
Q3. Which is the first question where d) is the correct answer?
a) Q1
b) Q2
c) Q4
d) Q3
Q4. Which is the first question where b) is the correct answer?
a) Q2
b) Q4
c) Q3
d) Q1
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Answer
Q1. d)
Q2. c)
Q3. a)
Q4. b)
Reasoning
Let's look at Q1 first, and check each possible option:
If Q1's answer was a):
...we'll leave checking this for now, because...
If Q1's answer was b):
...we'll leave checking this for now, because...
If Q1's answer was c):
it would reference itself and we'd learn nothing new, and we'd then have to check Q2.
So, let's start with Q2 first instead of Q1.
If Q2's answer was a):
an immediate contradiction, as Q4 can't be the first answer with a) as we've assumed Q2's answer is a).
If Q2's answer was b):
an immediate contradiction, as Q2 can't be the first answer with a) as we've assumed Q2's answer is b).
If Q2's answer was c):
Q3's answer would be a)
Q1's answer would be d)
confirming Q2's answer as c)
leaving Q4's only possible answer as b)
no contradiction.
If Q2's answer was d):
Q1's answer would be a) (*)
Q3's answer would be c)
Q4's answer would be d)
Q1's answer would be b)
but this contradicts the section marked (*).
Therefore, the only possible answer with no contradiction is when Q2's answer is c).
Puzzle 150
These 4-letter words can each have a letter added and then be rearranged to make a new 5-letter word.
In order, the letters added spell a 9-letter word.
HERB
BANG
KEEN
SUIT
QUAD
WHEY
CELL
TOIL
WILD
Puzzle Copyright © Kevin Stone
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Hint
In order, the added letters spell TELESCOPE.
Answers
The added letters spell TELESCOPE.
HERB + T becomes BERTH
BANG + E becomes BEGAN
KEEN + L becomes KNEEL
SUIT + E becomes SUITE
QUAD + S becomes SQUAD
WHEY + C becomes CHEWY
CELL + O becomes CELLO
TOIL + P becomes PILOT
WILD + E becomes WIELD
Puzzle 151
Can you complete this grid of letters?
Each line is a valid 5-letter word with its first and last letters missing.
The missing letters form a word when read downwards, and the same word appears both at the start and at the end.
What is the missing word?
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I |
N |
E |
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R |
O |
D |
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Y |
L |
O |
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O |
A |
S |
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E |
A |
T |
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Note: this puzzle isn't interactive, and the squares can't be clicked.
Puzzle Copyright © Kevin Stone
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Hint
The first missing letter is D, giving DineD.
Answer
DENTS.
D |
I |
N |
E |
D |
E |
R |
O |
D |
E |
N |
Y |
L |
O |
N |
T |
O |
A |
S |
T |
S |
E |
A |
T |
S |
Puzzle 152
Mixed Hurdle Trials - Logic Puzzles
At the recent BrainBashers Mixed National Hurdle trials, ten contestants competed for the coveted BB Shield.
There were numerous judges who made sure that the results were accurate, from their notes can you determine who finished where?
Crystal Ball finished before May Eye and Mike Stup, while Leigh Vamessage was victorious over May Eye and Laura DeLand.
Jack Pott was beaten by Holly Day, Mike Stup, and Justin Time.
Laura DeLand was beaten by Mike Stup, May Eye, and Crystal Ball, whereas Joe King beat Holly Day and Jack Pott, but lost to Laura DeLand and Inga Hootz.
Leigh Vamessage was beaten by Crystal Ball and Inga Hootz.
Inga Hootz was beaten by Justin Time, who, in turn, lost to Crystal Ball, but beat Holly Day and Jack Pott.
May Eye finished ahead of Mike Stup and Holly Day (who lost to Leigh Vamessage and Inga Hootz).
Puzzle Copyright © Kevin Stone
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Hint
Rewrite the clues so that those who finished ahead are written first.
Answer
Crystal Ball (CB)
Justin Time (JT)
Inga Hootz (IH)
Leigh Vamessage (LV)
May Eye (ME)
Mike Stup (MS)
Laura DeLand (LD)
Joe King (JK)
Holly Day (HD)
Jack Pott (JP)
Reasoning
If we number the clues, write each name using two letters, and rewrite the clues so that those who finished ahead are written first:
CB beat ME and MS
LV beat ME and LD
HD, MS, and JT, all beat JP
MS, ME, and CB, all beat LD
JK beat HD and JP
LD and IH both beat JK
CB and IH both beat LV
JT beat IH
CB beat JT
JT beat HD and JP
ME beat MS and HD
LV and IH both beat HD
We can start with the first piece of information given in (1)
By (1): CB ME
By (4): CB ME LD
By (6): CB ME LD JK
By (5): CB ME LD JK HD
By (3): CB ME LD JK HD JP
By (4) and (11): MS and ME both beat LD, but ME beat MS, so we can insert MS to give: CB ME MS LD JK HD JP
And...
By (9): CB JT
By (8): CB JT IH
By (7): CB JT IH LV
By (2): CB JT IH LV ME
We can now insert these to give: CB JT IH LV ME MS LD JK HD JP, and we have found all of the finishing positions.
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