Puzzle 33
W B H F S K F V J P Z
H S S H T J P P N W L
A F P W P N T D S W S
T R H S P L M V R G B
I D P B D W S N R T C
S R S F T D B K K F B
O M F R L Z F R K Y P
N J Z J S Z N M B J Q
E R Z F Q Z V G Y F V
P P F G F W Z W N R P
L B J V R J H F K T Z
U H F K Y F W J F S R
S S W C Q R Q Y H R S
O M W F P R Q J K H R
N M B W S K B J Y D Q
E T J Y P F D L R P F
Puzzle Copyright © Kevin Stone
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Hint
The question is somewhere in the grid.
Answer
Two.
The first column reads 'WHAT IS ONE PLUS ONE'.
Puzzle 34
Using all of the letters A to Z, each once only, complete these common words. There are currently 2 different answers, can you find them both?
-ai-e
s-ua-
-e-el
-o-ed
-na-e
fog--
c--mp
b--jo
-r-it
-re-t
-av-n
mu--c
mou--
Puzzle Copyright © Kevin Stone
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Hint
The first word begins with the letter M.
Answers
-ai-e = maize (MZ)
s-ua- = squad (QD)
-e-el = jewel (JW)
-o-ed = foxed (FX)
-na-e = knave (KV)
fog-- = foggy (GY)
c--mp = clump (LU)
b--jo = banjo (AN)
-r-it = orbit (OB)
-re-t = crept (CP)
-av-n = raven (RE)
mu--c = music (SI)
mou-- = mouth (TH)
Alternative Answers
Maize, squad, jewel, boxed, knave, foggy, clomp, banjo, fruit, crept, raven, music, mouth.
Can you find another?
Puzzle 35
Below are ten words that have been split in half.
The first column has the first 2 letters, and the second column has the last 2 letters.
Can you pair the letters and remake the ten common words?
bo af
br re
fo ne
go af
ho ke
jo ew
le ud
lo am
lo nd
so pe
Puzzle Copyright © Kevin Stone
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Hint
One of the words is gone.
Answers
bo + nd = bond
br + ew = brew
fo + am = foam
go + ne = gone
ho + pe = hope
jo + ke = joke
le + af = leaf
lo + af = loaf
lo + ud = loud
so + re = sore
Puzzle 36
At the local sweet shop, three particularly nice sweets are on special offer.
A Nobbler is over three times the price of a Sparkle.
Six Sparkles are worth more than a Wibbler.
A Nobbler, plus two Sparkles costs less than a Wibbler.
A Sparkle, a Wibbler and a Nobbler together cost 40p.
Can you determine the price of each type of sweet?
Puzzle Copyright © Kevin Stone
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Hint
Which sweet is the least expensive?
Answer
Sparkle = 4p
Wibbler = 23p
Nobbler = 13p
Reasoning
By (3) a Nobbler, plus two Sparkles costs less than a Wibbler, therefore a Wibbler must be the most expensive sweet.
By (1) a Nobbler is over three times the price of a Sparkle, therefore a Sparkle must be the cheapest sweet.
So the order of sweets, from the least to most expensive, is Sparkle, Nobbler, Wibbler.
If a Sparkle was 1p, by (2) a Wibbler could only be up to 5p, by (4) a Nobbler would cost at least 34p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 2p, by (2) a Wibbler could only be up to 11p, by (4) a Nobbler would cost at least 27p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
If a Sparkle was 3p, by (2) a Wibbler could only be up to 17p, by (4) a Nobbler would cost at least 20p, which is more than a Wibbler and isn't allowed as the Wibbler is the most expensive sweet.
So a Sparkle must be at least 4p.
If a Sparkle was 4p, by (1) a Nobbler must be at least 13p, by (4) a Wibbler would cost 23p – this combination matches all of the clues and is a possible solution.
If a Sparkle was 4p and a Nobbler 14p, by (4) a Wibbler would cost 22p. This would not satisfy (3). And if we increase the price of a Nobbler, (3) is never satisfied.
If a Sparkle was 5p, by (1) a Nobbler must be at least 16p, by (4) making a Wibbler at most 19p. This would not satisfy (3).
If we increase the price of a Sparkle or Nobbler further, (3) is will never be satisfied.
Therefore, the only solution we came across must be the correct one.
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