Puzzle 21
During a recent BrainBashers thinking contest(!), the total number of points scored by the first six players was 103 and every score was above zero.
The first player scored half the points of the second player, who in turn scored 6 points fewer than the third player.
The third player in turn scored two thirds the points of the fourth player.
The fifth player managed to score the same number of points as the difference between the first and fourth player's points.
Finally, the sixth player scored 14 fewer points than the fifth player.
Can you determine how many points the sixth player managed to score?
Puzzle Copyright © Kevin Stone
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Hint
The fourth player is the key to this tricky question.
Answer
9 points.
Respectively the scores were 7, 14, 20, 30, 23, 9.
Reasoning
If we label the six players A, B, C, D, E, and F, we know that:
[1] A + B + C + D + E + F = 103
and from the clues:
A = B ÷ 2
B = C – 6
C = D x 2 ÷ 3
E = D – A
F = E – 14
If instead we choose E = A – D, we'd later see that we end up with a negative value for E, which isn't allowed.
Since D is the letter we're missing information for, it's best to find all of the other letters in terms of D.
These steps are left as an exercise (use C in the equation for B, etc), but the result is:
A = ( D – 9) ÷ 3
B = (2D – 18) ÷ 3
C = (2D ) ÷ 3
D = (3D ) ÷ 3
E = (2D + 9) ÷ 3
F = (2D – 33) ÷ 3
Writing it as D = 3D ÷ 3 makes it slightly clearer to see, when adding in the next step.
We can then use these in [1] to find that 12D = 360, so D = 30.
Therefore, F = 9.
Puzzle 22
What four-digit number has...
...Digit 2 smaller than Digit 4 which is two thirds of Digit 1 which is two thirds of Digit 3 which is three times Digit 2?
Puzzle Copyright © Kevin Stone
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Hint
Look at Digit 3 first.
Answer
6394.
Reasoning
Labelling the clues:
Digit 2 is smaller than Digit 4
Digit 4 is two thirds of Digit 1
Digit 1 is two thirds of Digit 3
Digit 3 is three times Digit 2
Using (4), Digit 3 can only be 3, 6 or 9 (as it's 3 x Digit 2).
Therefore, using (4), Digit 2 can only be 1, 2 or 3.
Using (3), Digit 1 can only be 2, 4 or 6 (as it's two thirds of Digit 3).
However, using (2), the only possible value for Digit 1 that we can find two thirds of is 6.
So, using (2), Digit 4 is 4.
So far, we have 6??4.
Using (3), Digit 1 is two thirds of Digit 3, so Digit 3 must be 9.
And, by (4), Digit 2 must be 3.
Giving 6394.
Puzzle 23
Can you find the number that best completes this puzzle?
Puzzle Copyright © Kevin Stone
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Hint
The answer involves a square root.
Answer
4.
The middle of each triangle contains the square root of the sum of the three surrounding numbers.
Puzzle 24
During the recent BrainBashers Football Competition, 5 teams were competing.
Each team played each other just once, with 2 points for a win, 1 point for a draw, and 0 points for a loss.
However, the rain damaged the final scoresheet, and this is all that could be read of the final points after all of the matches:
Rugby 6
Grimsby 5
Hereford 4
Lichfield 2
Reading {?}
Can you work out how many points Reading ended the season with?
Puzzle Copyright © Kevin Stone
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Share link – www.brainbashers.com/puzzle/zbil
Hint
How many games took place?
Answer
3.
Reasoning
There were 5 teams in the league, and every team played every other, so there were a total of 10 games played:
Rugby vs Grimsby
Rugby vs Hereford
Rugby vs Lichfield
Rugby vs Reading
Grimsby vs Hereford
Grimsby vs Lichfield
Grimsby vs Reading
Hereford vs Lichfield
Hereford vs Reading
Lichfield vs Reading
We know that 2 points were allocated for each game played. Which means that there were a total of 20 points over the 10 games.
Since the given results add to 17, the remaining 3 points belong to Reading.
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