Random Puzzles 

Workings

Hint
One possibility answer might be associated with an apiary.

Answer
Common words: beekeeper, beekeepers, beekeeping, freebee, freebees, freewheel, freewheeled, freewheeling, freewheels, peewee, peewees, reengineer, reengineered, reengineering, reengineers, squeegee, squeegeed, squeegeeing, squeegees, teepee, teepees.

All words: beebee, beebees, beekeeper, beekeepers, beekeeping, beekeepings, beetleweed, beetleweeds, cheekteeth, deepfreeze, deepfreezes, deepfreezing, deerweed, deerweeds, freebee, freebees, freesheet, freesheets, freewheel, freewheeled, freewheeler, freewheelers, freewheeling, freewheelingly, freewheelings, freewheels, geechee, geechees, greegree, greegrees, greenkeeper, greenkeepers, greenleek, greenskeeper, greenskeepers, greenweed, greenweeds, leechee, leechees, peebeen, peebeens, peesweep, peesweeps, peetweet, peetweets, peewee, peewees, preengineered, reengineer, reengineered, reengineering, reengineers, sleeveen, sleeveens, sneezeweed, sneezeweeds, squeegee, squeegeed, squeegeeing, squeegees, streetkeeper, streetkeepers, teepee, teepees, teetee, treecreeper, treecreepers, tweedledee, tweedledeed, tweedledeeing, tweedledees, veepee, veepees, weewee, weeweed, weeweeing, weewees.

Workings

Hint
Look at the first letters of the words.

Answer
Alphabet.

The first letters of the words are spelling BrainBashers.

Workings

Hint
Could Alex Ambleton have won?

Answer
Taylor Tripton won with Midday Night.

Reasoning
Before we begin the reasoning, let's look at the hint: 'Could Alex Ambleton have won?'. There are three horses in the puzzle, and Alex Ambleton is stated to have won with all three of them. We know that none of the statements were fully true, so Alex couldn't have won otherwise one of the statements would have been fully true.

However, we don't need the hint to solve the puzzle.

By grouping the clues together, we have:

1. Frankie Flanton won with Morning Sunset.
2. Frankie Flanton won with Evening Sunrise.
3. Frankie Flanton won with Evening Sunrise.

4. Sam Spinton won with Midday Night.
5. Sam Spinton won with Midday Night.
6. Sam Spinton won with Midday Night.
7. Sam Spinton won with Morning Sunset.

8. Taylor Tripton won with Morning Sunset.
9. Taylor Tripton won with Evening Sunrise.

10. Alex Ambleton won with Midday Night.
11. Alex Ambleton won with Morning Sunset.
12. Alex Ambleton won with Evening Sunrise.

We know that none of these statements were fully true, so, we know that (for example) it wasn't Frankie Flanton with Morning Sunset.

We can create a grid of all the possibilities and place an X where we know that it can't have been that combination:

We now have an X for all but 3 possibilities, and we know that exactly 6 of the clues must be half true.

So …

… if it was Frankie Flanton with Midday Night then exactly 7 clues would be half true (clues 1, 2, 3, 4, 5, 6, 10).

… if it was Sam Spinton with Evening Sunrise then exactly 8 clues would be half true (clues 4, 5, 6, 7, 2, 3, 9, 12).

… if it was Taylor Tripton with Midday Night then exactly 6 clues would be half true (clues 8, 9, 4, 5, 6, 10), and this must be the correct answer.

Workings

Hint
Going down and across the floor isn't the only route.

Answer
40 feet.

Explanation Diagram
If you imagine the room to be a cardboard box, you can 'unfold' the room in various ways, and each route gives a different answer.



We can use Pythagoras' theorem (a² + b² = c²) to calculate the distances:
   distance² = horizontal² + vertical²
   distance = √(horizontal² + vertical²)

Route #1
   distance = 1 + 30 + 11 = 42 feet.

Route #2
   horizontal = 6 + 30 + 6 = 42 feet.
   vertical = 10 feet.
   distance = √(42² + 10²) ≈ 43.174 feet.

Route #3
   horizontal = 1 + 30 + 6 = 37 feet.
   vertical = 6 + 11 = 17 feet.
   distance = √(37² + 17²) ≈ 43.178 feet.

Route #4
   horizontal = 1 + 30 + 1 = 32 feet.
   vertical = 6 + 12 + 6 = 24 feet.
   distance = √(32² + 24²) = 40 feet.