At the local play group for babies and toddlers, I was asking about the number of teddies each of child had.
The four children are aged 1, 2, 3 and 4.
Remarkably, the children have one, two, three and four teddies, although not necessarily respectively.
Dale has more teddies that their age. Jesse is older than Morgan. Curiously only one child has the same number of teddies as their age. Pat has fewer teddies than Jesse and the child aged 3 has two teddies. Pat is the youngest.
Reasoning
Take the numbers in pairs, square the first, and reverse the digits.
1 1 (1 x 1 = 1, reversed is 1)
2 4 (2 x 2 = 4, reversed is 4)
3 9 (3 x 3 = 9, reversed is 9)
4 61 (4 x 4 = 16, reversed is 61)
5 52 (5 x 5 = 25, reversed is 52)
6 63 (6 x 6 = 36, reversed is 63)
7 94 (7 x 7 = 49, reversed is 94)
so we require:
8 46 (8 x 8 = 64, reversed is 46)
