Puzzle 5
Can you find anagrams of the following words?
coagulate
cavitates
bacterial
balancers
headlamps
milestone
telephony
dignifies
unnoticed
Puzzle Copyright © Kevin Stone
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Hint
The first letters of the words are: C, A, C, B, L, L, P, S, C.
Answers
coagulate = catalogue
cavitates = activates
bacterial = calibrate
balancers = barnacles
headlamps = lampshade
milestone = lemoniest or limestone
telephony = polythene
dignifies = signified
unnoticed = continued
Puzzle 6
Using the clues below can you find 8 four-letter words?
Once you have placed the words into the correct order you will find that each word is different from the previous word by only one letter.
For example, FARE may be followed by FIRE, etc.
Additional items
Insufficiently heated
A female equine
Insufficiently cooled
Pottery
A bump on a toad?
The middle of an apple
Insulated electrical wire
Puzzle Copyright © Kevin Stone
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Hint
One of the words is Warm.
Answer
Insufficiently heated = cold
Insulated electrical wire = cord
The middle of an apple = core
Additional items = more
A female equine = mare
Pottery = ware
A bump on a toad? = wart
Insufficiently cooled = warm
Puzzle 7
Assign every letter of the alphabet its numerical value: A=1, B=2, C=3, and so on, up to Z=26.
Can you find any common 6-letter words that have a total over 115?
For example, WIZARD = 23 + 9 + 26 + 1 + 18 + 4 = 81.
Puzzle Copyright © Kevin Stone
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Hint
There are many answers, however, Z doesn't appear very often.
Answers
Choose from: luxury, struts, stylus, syrupy, trusts, twisty.
Other less common words include: scuzzy, syrups, syzygy, trouty, trusty, tryout, trysts.
Puzzle 8
Alex's child, Drew, is exactly one fifth of Alex's age. In 21 years, Alex will be exactly twice Drew's age. How old is Drew now?
Billie is exactly seven times the age of his child, Glen. In 8 years, Billie will be three times the age of Glen. How old is Glen now?
Puzzle Copyright © Kevin Stone
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Hint
A little bit of algebra might help.
Answers
Drew is 7 years old.
Glen is 4 years old.
Answer #1
The first question involves Drew (D) and Alex (A).
Drew is currently one fifth of Alex's age, so:
(1) A = D x 5
In 21 years, Alex will be twice their age, so:
(2) A + 21 = (D + 21) x 2
Using (1) in (2) gives:
A + 21 = (D + 21) x 2
5D + 21 = (D + 21) x 2
5D + 21 = 2D + 42
3D = 21
D = 7
So Drew is 7 (and Alex is 35).
Answer #2
The second question involves Glen (G) and Billie (B).
Billie is exactly seven times the age of Glen:
(3) B = G x 7
In 8 years, Billie will be three times the age of Glen, so:
(4) B + 8 = (G + 8) x 3
Using (3) in (4) gives:
B + 8 = (G + 8) x 3
7G + 8 = (G + 8) x 3
7G + 8 = 3G + 24
4G = 16
G = 4
So Glen is 4 (and Billie is 28).
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