Using all of the letters A to Z, each once only, complete these common words. ban--a-i-et-aiz-s--thna-e--eco--ocu--la-e--nkf-xbe--ree-ui-ot-erwis--oast
Answers ban- = bank (K)-a-i-et = cabinet (CBN)-aiz- = maize (ME)s--th = sixth (IX)na-e- = navel (VL)-eco- = decoy (DY)-ocu- = focus (FS)-la-e = glaze (GZ)--nk = junk (JU)f-x = fox (O)be--re = beware (WA)e-ui- = equip (QP)ot-er = otter (T)wis- = wish (H)-oast = roast (R)
This puzzle isn't guaranteed to have a unique answer, can you find another?
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Puzzle 155
During the recent BrainBashers cipher convention, a binary code contest took place.
The contest consisted of a binary code transmission where the spaces between the letters were missing and there was no punctuation.
Each letter of the alphabet was translated into its binary equivalent based on its position in the alphabet. The resulting code was then blocked in groups of five digits.
a=1, b=10, c=11, d=100, e=101, f=110, g=111, h=1000, i=1001, j=1010, k=1011, l=1100, m=1101, n=1110, o=1111, p=10000, q=10001, r=10010, s=10011, t=10100, u=10101, v=10110, w=10111, x=11000, y=11001, z=11010
Answer
If the sum of the digits is divisible by nine, so is the number.
Add up all of the digits in the number and see if the sum is divisible by 9. If you still can't tell, you can add those digits again to see if the new sum is divisible by 9. You can keep going until you the sum is obviously divisible by 9 or not.
For example, is 486451464 divisible by 9?
Do 4 + 8 + 6 + 4 + 5 + 1 + 4 + 6 + 4 = 42.
Is 42 divisible by 9? Not sure, you can then do:
4 + 2 = 6. Which clearly isn't divisible by 9. So our original number, 486451464, isn't either.
