During the recent BrainBashers cipher convention, a binary code contest took place.
The contest consisted of a binary code transmission where the spaces between the letters were missing and there was no punctuation.
Each letter of the alphabet was translated into its binary equivalent based on its position in the alphabet. The resulting code was then blocked in groups of five digits.
a=1, b=10, c=11, d=100, e=101, f=110, g=111, h=1000, i=1001, j=1010, k=1011, l=1100, m=1101, n=1110, o=1111, p=10000, q=10001, r=10010, s=10011, t=10100, u=10101, v=10110, w=10111, x=11000, y=11001, z=11010
Hint
Look at the letter positions in the alphabet.
Answer
R.
If you take the alphabetic positions of each letter in a row, the total is always 56.
Double-Checking
Y + G + W + A = 25 + 7 + 23 + 1 = 56
K + L + R + O = 11 + 12 + 18 + 15 = 56
Z + J + P + D = 26 + 10 + 16 + 4 = 56
V + F + T + H = 22 + 6 + 20 + 8 = 56
??
Puzzle 204
Which pair of letters comes next in this sequence:
