     Puzzle 81 Below you will find 10 well-known six letter words, with only their endings remaining. Can you determine the words? ...era ...cil ...uld ...nis ...nda ...phy ...may ...ese ...eum ...axy [Puzzle Code = ZJMF] Copyright © Kevin Stone    Direct Link: www.brainbashers.com?ZJMF Hint: These are the first letters of the words: C, P, S, T, A, T, D, C, M, G. Answer: ...era >> camera ...cil >> pencil ...uld >> should ...nis >> tennis ...nda >> agenda ...phy >> trophy ...may >> dismay ...ese >> cheese ...eum >> museum ...axy >> galaxy Puzzle 82 How many squares, of any size, can you find on this chess board that do not contain a Rook? [Puzzle Code = ZDPX] Copyright © Kevin Stone    Direct Link: www.brainbashers.com?ZDPX Hint: There are no squares of size 5x5. Answer: 125. There are 61 squares of size 1x1. There are 39 squares of size 2x2. There are 20 squares of size 3x3. There are 5 squares of size 4x4. A total of 61 + 39 + 20 + 5. Puzzle 83 Below are six animals that have been split. Take a set of three letters from the left column, and a set of three letters from the right column and merge them together again, without changing the order of the letters in each half. Matching sets will not necessarily be on the same row. For example WMB + OAT and OAT + WMB both equal WOMBAT as the order of the letters OAT, and WMB remain the same. For another example, RABBIT could become RBT + ABI. CYO ARU WLS DNE EAR FEE OKY OTE RRT JAR AGU BVE [Puzzle Code = ZIFY] Copyright © Kevin Stone    Direct Link: www.brainbashers.com?ZIFY Hint: The first letters of the animals are B, C, D, F, J, W. Answer: Beaver, coyote, donkey, ferret, jaguar, walrus.EAR + BVE = BEAVER CYO + OTE = COYOTE OKY + DNE = DONKEY RRT + FEE = FERRET AGU + JAR = JAGUAR WLS + ARU = WALRUS Puzzle 84 During a recent BrainBashers thinking contest, the total number of points scored by the first six players was 103 and every score was above zero. The first player scored half the points of the second player, who in turn scored 6 points fewer than the third player. The third player in turn scored two thirds the points of the fourth player. The fifth player managed to score the same number of points as the difference between the first and fourth player's points. Finally, the sixth player scored 14 fewer than the fifth player. Can you determine how many points the sixth player managed to score? [Puzzle Code = ZRIL] Copyright © Kevin Stone    Direct Link: www.brainbashers.com?ZRIL Hint: The fourth player is the key to this tricky question. Answer: 9 points. Respectively the scores were 7, 14, 20, 30, 23, 9. If the six player were A, B, C, D, E and F we know that:A + B + C + D + E + F = 103      and    A = B ÷ 2    B = C - 6    C = D x 2 ÷ 3    E = D - A             (see note at end)    F = E - 14 Since D is the letter we're missing information for, it's best to find all of the other letters in terms of D. These steps are left as an exercise, but the result is: A = (2D - 18) ÷ 6 B = (2D - 18) ÷ 3 C = 2D ÷ 3 E = (2D + 9) ÷ 3 F = (2D - 33) ÷ 3 We can then use these all in  to find that D = 30. Which allows us to find F = 9. Small note: if we chose E = A - D (instead of E = D - A) we'd end up with a negative value for E, which isn't allowed.     