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There are 61 squares of size 1x1. There are 39 squares of size 2x2. There are 20 squares of size 3x3. There are 5 squares of size 4x4.
A total of 61 + 39 + 20 + 5.
Puzzle 83
Below are six animals that have been split.
Take a set of three letters from the left column, and a set of three letters from the right column and merge them together again, without changing the order of the letters in each half.
Matching sets will not necessarily be on the same row.
For example WMB + OAT and OAT + WMB both equal WOMBAT as the order of the letters OAT, and WMB remain the same.
For another example, RABBIT could become RBT + ABI.
Hint: The fourth player is the key to this tricky question.
Answer: 9 points.
Respectively the scores were 7, 14, 20, 30, 23, 9.
If the six player were A, B, C, D, E and F we know that:
A + B + C + D + E + F = 103 [1]
and
A = B ÷ 2
B = C  6
C = D x 2 ÷ 3
E = D  A (see note at end)
F = E  14
Since D is the letter we're missing information for, it's best to find all of the other letters in terms of D. These steps are left as an exercise, but the result is:
A = (2D  18) ÷ 6
B = (2D  18) ÷ 3
C = 2D ÷ 3
E = (2D + 9) ÷ 3
F = (2D  33) ÷ 3
We can then use these all in [1] to find that D = 30. Which allows us to find F = 9.
Small note: if we chose E = A  D (instead of E = D  A) we'd end up with a negative value for E, which isn't allowed.
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