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Daily Sudoku Answer 



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May 15 - Hard
Puzzle Copyright © Kevin Stone

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Reasoning 



R1C1 is the only square in row 1 that can be <6>

R6C8 is the only square in row 6 that can be <4>

R7C3 is the only square in row 7 that can be <5>

R9C9 is the only square in column 9 that can be <4>

R8C9 is the only square in column 9 that can be <8>

R7C5 is the only square in row 7 that can be <8>

R7C6 is the only square in row 7 that can be <4>

R2C5 is the only square in row 2 that can be <4>

R9C1 is the only square in column 1 that can be <8>

Intersection of row 3 with block 2. The values <25> only appears in one or more of squares R3C4, R3C5 and R3C6 of row 3. These squares are the ones that intersect with block 2. Thus, the other (non-intersecting) squares of block 2 cannot contain these values.

R1C5 - removing <5> from <357> leaving <37>

R2C4 - removing <5> from <35679> leaving <3679>

Intersection of column 3 with block 4. The values <36> only appears in one or more of squares R4C3, R5C3 and R6C3 of column 3. These squares are the ones that intersect with block 4. Thus, the other (non-intersecting) squares of block 4 cannot contain these values.

R4C2 - removing <3> from <1238> leaving <128>

R5C2 - removing <3> from <12379> leaving <1279>

R6C2 - removing <3> from <12378> leaving <1278>

Intersection of column 7 with block 6. The values <38> only appears in one or more of squares R4C7, R5C7 and R6C7 of column 7. These squares are the ones that intersect with block 6. Thus, the other (non-intersecting) squares of block 6 cannot contain these values.

R5C9 - removing <3> from <135> leaving <15>

Intersection of block 9 with column 8. The value <1> only appears in one or more of squares R7C8, R8C8 and R9C8 of block 9. These squares are the ones that intersect with column 8. Thus, the other (non-intersecting) squares of column 8 cannot contain this value.

R2C8 - removing <1> from <1579> leaving <579>

R4C8 - removing <1> from <1256> leaving <256>

R5C8 - removing <1> from <1256> leaving <256>

Squares R4C7<138>, R5C7<13> and R6C7<138> in column 7 form a comprehensive naked triplet. These 3 squares can only contain the 3 possibilities <138>. Since each of the squares must contain one of the possibilities, they can be eliminated from the other squares in the column.

R3C7 - removing <1> from <179> leaving <79>

R3C3 is the only square in row 3 that can be <1>

R6C3 can only be <3>

R4C3 can only be <6>

R5C3 can only be <9>

R2C9 is the only square in row 2 that can be <1>

R5C9 can only be <5>

R1C9 can only be <3>

R4C8 can only be <2>

R1C5 can only be <7>

R4C6 can only be <3>

R5C8 can only be <6>

R2C4 is the only square in row 2 that can be <3>

R2C6 is the only square in row 2 that can be <6>

R3C7 is the only square in row 3 that can be <7>

R7C7 can only be <9>

R7C4 can only be <7>

R9C8 can only be <1>

R9C5 can only be <3>

R8C8 can only be <7>

R6C4 can only be <1>

R8C6 can only be <9>

R8C1 can only be <2>

R3C6 can only be <2>

R9C2 can only be <9>

R8C5 can only be <1>

R3C5 can only be <5>

R6C6 can only be <7>

R6C7 can only be <8>

R4C4 can only be <5>

R8C4 can only be <6>

R5C5 can only be <2>

R6C2 can only be <2>

R4C7 can only be <1>

R8C2 can only be <3>

R5C1 can only be <7>

R1C2 can only be <5>

R1C8 can only be <9>

R2C2 can only be <7>

R2C8 can only be <5>

R2C1 can only be <9>

R3C4 can only be <9>

R4C2 can only be <8>

R5C7 can only be <3>

R5C2 can only be <1>



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