Puzzle 13
During the recent BrainBashers cipher convention, a Morse code contest took place.
The contest consisted of a Morse code transmission where the spaces between the letters and words were missing.
Can you find the ten names for pet cats?
Luckily, BrainBashers has provided you with a list of the Morse code characters:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Puzzle Copyright © Kevin Stone
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Hint
The first letters of the words are: F, T, W, S, F, T, T, T, S, M.
Answers
Fluffy
Tiger
Whiskers
Spot
Felix
Tom
Tabby
Tiddles
Socks
Mittens
Puzzle 14
Using all of the letters A to Z, each once only, complete these common words:
ba-g-
d--ed
dia--
-uo-a
i-de-
-o-el
-um-s
py--y
g-ou-
--nal
tra--
-umb-
d--ty
Puzzle Copyright © Kevin Stone
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Hint
The 4th word begins with the letter Q.
Answers
ba-g- = badge (DE)
d--ed = dazed (AZ)
dia-- = diary (RY)
-uo-a = quota (QT)
i-de- = index (NX)
-o-el = vowel (VW)
-um-s = bumps (BP)
py--y = pygmy (GM)
g-ou- = ghoul (HL)
--nal = final (FI)
tra-- = track (CK)
-umb- = jumbo (JO)
d--ty = dusty (US)
Puzzle 15
You have a very large number of generic plastic building blocks, each in the shape of a cube.
Think about how many cubes you would need in order to construct a giant cube with 16 small cubes along each edge.
If you were to then remove the outside layer, how many small cubes would you have removed?
Puzzle Copyright © Kevin Stone
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Hint
How large would the smaller cube be?
Answer
1,352 small cubes.
Reasoning
The original large cube with 16 small cubes along each edge would require 16 x 16 x 16 = 4,096 small cubes.
Removing the outside layer would leave a large cube now with 14 small cubes along each edge (which requires 14 x 14 x 14 = 2,744 small cubes).
It isn't 15 small cubes because you're removing both ends of an edge.
Therefore, you have removed 4,096 – 2,744 = 1,352 small cubes.
Puzzle 16
What number comes next in this sequence:
1 23 124 1251 26127 128129 {?}
Puzzle Copyright © Kevin Stone
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Hint
Try removing the spaces from the sequence.
Answer
1301311 or 1210121.
Reasoning
Removing spaces from the original sequence gives:
1 23 124 1251 26127 128129
123124125126127128129
Now adding spaces back in, in the correct place:
123 124 125 126 127 128 129
The next few terms could be:
130 131 132
or
1210 1211 1212
Add these to the end:
123 124 125 126 127 128 129 130 131 132
or
123 124 125 126 127 128 129 1210 1211 1212
Remove the spaces again:
123124125126127128129130131132
or
123124125126127128129121012111212
Now break the sequence into chunks of increasing size:
1 23 124 1251 26127 128129 1301311
or
1 23 124 1251 26127 128129 1210121
So the missing term is 1301311 or 1210121.
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